Optimal. Leaf size=303 \[ \frac{2 b^{5/4} \left (\sqrt{a}+\sqrt{b} x\right ) \sqrt{\frac{a+b x^2}{\left (\sqrt{a}+\sqrt{b} x\right )^2}} \text{EllipticF}\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt [4]{a} \sqrt{c}}\right ),\frac{1}{2}\right )}{5 a^{3/4} c^{7/2} \sqrt{a+b x^2}}-\frac{4 b^{5/4} \left (\sqrt{a}+\sqrt{b} x\right ) \sqrt{\frac{a+b x^2}{\left (\sqrt{a}+\sqrt{b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt [4]{a} \sqrt{c}}\right )|\frac{1}{2}\right )}{5 a^{3/4} c^{7/2} \sqrt{a+b x^2}}+\frac{4 b^{3/2} \sqrt{c x} \sqrt{a+b x^2}}{5 a c^4 \left (\sqrt{a}+\sqrt{b} x\right )}-\frac{4 b \sqrt{a+b x^2}}{5 a c^3 \sqrt{c x}}-\frac{2 \sqrt{a+b x^2}}{5 c (c x)^{5/2}} \]
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Rubi [A] time = 0.222403, antiderivative size = 303, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.316, Rules used = {277, 325, 329, 305, 220, 1196} \[ \frac{2 b^{5/4} \left (\sqrt{a}+\sqrt{b} x\right ) \sqrt{\frac{a+b x^2}{\left (\sqrt{a}+\sqrt{b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt [4]{a} \sqrt{c}}\right )|\frac{1}{2}\right )}{5 a^{3/4} c^{7/2} \sqrt{a+b x^2}}-\frac{4 b^{5/4} \left (\sqrt{a}+\sqrt{b} x\right ) \sqrt{\frac{a+b x^2}{\left (\sqrt{a}+\sqrt{b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt [4]{a} \sqrt{c}}\right )|\frac{1}{2}\right )}{5 a^{3/4} c^{7/2} \sqrt{a+b x^2}}+\frac{4 b^{3/2} \sqrt{c x} \sqrt{a+b x^2}}{5 a c^4 \left (\sqrt{a}+\sqrt{b} x\right )}-\frac{4 b \sqrt{a+b x^2}}{5 a c^3 \sqrt{c x}}-\frac{2 \sqrt{a+b x^2}}{5 c (c x)^{5/2}} \]
Antiderivative was successfully verified.
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Rule 277
Rule 325
Rule 329
Rule 305
Rule 220
Rule 1196
Rubi steps
\begin{align*} \int \frac{\sqrt{a+b x^2}}{(c x)^{7/2}} \, dx &=-\frac{2 \sqrt{a+b x^2}}{5 c (c x)^{5/2}}+\frac{(2 b) \int \frac{1}{(c x)^{3/2} \sqrt{a+b x^2}} \, dx}{5 c^2}\\ &=-\frac{2 \sqrt{a+b x^2}}{5 c (c x)^{5/2}}-\frac{4 b \sqrt{a+b x^2}}{5 a c^3 \sqrt{c x}}+\frac{\left (2 b^2\right ) \int \frac{\sqrt{c x}}{\sqrt{a+b x^2}} \, dx}{5 a c^4}\\ &=-\frac{2 \sqrt{a+b x^2}}{5 c (c x)^{5/2}}-\frac{4 b \sqrt{a+b x^2}}{5 a c^3 \sqrt{c x}}+\frac{\left (4 b^2\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{a+\frac{b x^4}{c^2}}} \, dx,x,\sqrt{c x}\right )}{5 a c^5}\\ &=-\frac{2 \sqrt{a+b x^2}}{5 c (c x)^{5/2}}-\frac{4 b \sqrt{a+b x^2}}{5 a c^3 \sqrt{c x}}+\frac{\left (4 b^{3/2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{a+\frac{b x^4}{c^2}}} \, dx,x,\sqrt{c x}\right )}{5 \sqrt{a} c^4}-\frac{\left (4 b^{3/2}\right ) \operatorname{Subst}\left (\int \frac{1-\frac{\sqrt{b} x^2}{\sqrt{a} c}}{\sqrt{a+\frac{b x^4}{c^2}}} \, dx,x,\sqrt{c x}\right )}{5 \sqrt{a} c^4}\\ &=-\frac{2 \sqrt{a+b x^2}}{5 c (c x)^{5/2}}-\frac{4 b \sqrt{a+b x^2}}{5 a c^3 \sqrt{c x}}+\frac{4 b^{3/2} \sqrt{c x} \sqrt{a+b x^2}}{5 a c^4 \left (\sqrt{a}+\sqrt{b} x\right )}-\frac{4 b^{5/4} \left (\sqrt{a}+\sqrt{b} x\right ) \sqrt{\frac{a+b x^2}{\left (\sqrt{a}+\sqrt{b} x\right )^2}} E\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt [4]{a} \sqrt{c}}\right )|\frac{1}{2}\right )}{5 a^{3/4} c^{7/2} \sqrt{a+b x^2}}+\frac{2 b^{5/4} \left (\sqrt{a}+\sqrt{b} x\right ) \sqrt{\frac{a+b x^2}{\left (\sqrt{a}+\sqrt{b} x\right )^2}} F\left (2 \tan ^{-1}\left (\frac{\sqrt [4]{b} \sqrt{c x}}{\sqrt [4]{a} \sqrt{c}}\right )|\frac{1}{2}\right )}{5 a^{3/4} c^{7/2} \sqrt{a+b x^2}}\\ \end{align*}
Mathematica [C] time = 0.0126724, size = 56, normalized size = 0.18 \[ -\frac{2 x \sqrt{a+b x^2} \, _2F_1\left (-\frac{5}{4},-\frac{1}{2};-\frac{1}{4};-\frac{b x^2}{a}\right )}{5 (c x)^{7/2} \sqrt{\frac{b x^2}{a}+1}} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.025, size = 219, normalized size = 0.7 \begin{align*}{\frac{2}{5\,{x}^{2}{c}^{3}a} \left ( 2\,\sqrt{{\frac{bx+\sqrt{-ab}}{\sqrt{-ab}}}}\sqrt{2}\sqrt{{\frac{-bx+\sqrt{-ab}}{\sqrt{-ab}}}}\sqrt{-{\frac{bx}{\sqrt{-ab}}}}{\it EllipticE} \left ( \sqrt{{\frac{bx+\sqrt{-ab}}{\sqrt{-ab}}}},1/2\,\sqrt{2} \right ){x}^{2}ab-\sqrt{{ \left ( bx+\sqrt{-ab} \right ){\frac{1}{\sqrt{-ab}}}}}\sqrt{2}\sqrt{{ \left ( -bx+\sqrt{-ab} \right ){\frac{1}{\sqrt{-ab}}}}}\sqrt{-{bx{\frac{1}{\sqrt{-ab}}}}}{\it EllipticF} \left ( \sqrt{{ \left ( bx+\sqrt{-ab} \right ){\frac{1}{\sqrt{-ab}}}}},{\frac{\sqrt{2}}{2}} \right ){x}^{2}ab-2\,{b}^{2}{x}^{4}-3\,ab{x}^{2}-{a}^{2} \right ){\frac{1}{\sqrt{cx}}}{\frac{1}{\sqrt{b{x}^{2}+a}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{b x^{2} + a}}{\left (c x\right )^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\sqrt{b x^{2} + a} \sqrt{c x}}{c^{4} x^{4}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [C] time = 62.677, size = 53, normalized size = 0.17 \begin{align*} \frac{\sqrt{a} \Gamma \left (- \frac{5}{4}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{5}{4}, - \frac{1}{2} \\ - \frac{1}{4} \end{matrix}\middle |{\frac{b x^{2} e^{i \pi }}{a}} \right )}}{2 c^{\frac{7}{2}} x^{\frac{5}{2}} \Gamma \left (- \frac{1}{4}\right )} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{b x^{2} + a}}{\left (c x\right )^{\frac{7}{2}}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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